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30(10x)^2=60000
We move all terms to the left:
30(10x)^2-(60000)=0
a = 3010; b = 0; c = -60000;
Δ = b2-4ac
Δ = 02-4·3010·(-60000)
Δ = 722400000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{722400000}=\sqrt{160000*4515}=\sqrt{160000}*\sqrt{4515}=400\sqrt{4515}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-400\sqrt{4515}}{2*3010}=\frac{0-400\sqrt{4515}}{6020} =-\frac{400\sqrt{4515}}{6020} =-\frac{20\sqrt{4515}}{301} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+400\sqrt{4515}}{2*3010}=\frac{0+400\sqrt{4515}}{6020} =\frac{400\sqrt{4515}}{6020} =\frac{20\sqrt{4515}}{301} $
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